Struct template unpack_expr . Boost , The Boost C++ Libraries BoostBook Documentation Subset , Reference

Struct template unpack_expr

boost::proto::functional::unpack_expr — A PolymorphicFunctionObject equivalent to the proto::unpack_expr() function.

Synopsis

// In header: <boost/proto/make_expr.hpp>
template<typename Tag, typename Domain = proto::deduce_domain> 
struct unpack_expr :  proto::callable {
  // member classes/structs/unions
  template<typename This, typename Sequence> 
  struct result<This(Sequence)> :  
    proto::result_of::unpack_expr<
      Tag,
      Domain,
      typename boost::remove_reference< Sequence >::type
    >
  {
  };
  // public member functions
  template<typename Sequence> 
    typename proto::result_of::unpack_expr< Tag, Domain, Sequence const >::type const 
    operator()(Sequence const &) const;
};

Description

Во всех случаях<proto::functional::unpack_expr<Tag, Domain>()(seq)>эквивалентно<proto::unpack_expr()<Tag, Domain>(seq)>.

<proto::functional::unpack_expr<Tag>()(seq)>эквивалентно<proto::unpack_expr()<Tag>(seq)>.

`unpack_expr` public member functions

<
```
template<typenameSequence>
 typenameproto::result_of::unpack_expr<Tag,Domain,Sequenceconst>::typeconst
 operator()(Sequenceconst&sequence)const;
```
>
Постройте узел выражения с типом тега<Tag>и в домене<Domain>.
Параметры:
<sequence>
Последовательность слияний
Возвращение:
<proto::unpack_expr<Tag, Domain>(sequence)>

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Struct template unpack_expr

Boost , The Boost C++ Libraries BoostBook Documentation Subset , Reference

Boost C++ Libraries

Struct template unpack_expr

Synopsis

Description

unpack_expr public member functions

`unpack_expr` public member functions